Talk:Evolution & Amalgamation/@comment-30650229-20170401193126/@comment-30650229-20170407220037

Thanks for getting me out of my doubts. Now I see that:

3*[2]+1*       is  3*=(1*+1*)+0*, +1*               i.e. method A

3*[1]+2*[1]   is  3*=(1*+0*)+0*, +2*=(1*+0*)    i.e. method C

3*[3]+1*      is  3*=(1*+0*)+1*, +1*                i.e. method B

So according to this B and C are the best methods and should have the same result. The A discarded.